
A=∫0π/4cosxdx+∫π/4πsinxdx+∫π5π/4−sinxdx+∫5π/43π/2−cosxdx
A=(sinx)0π/4+(−cosx)π/4π+(cosx)π5π/4+(sinx)5π/43π/2
A=21+21+1+1−21+1−21=3
A2+A=12
JEE Main 2026 — Mathematics Calculus
Let the area of the region bounded by the curve y=max{sinx,cosx}, lines x=0,x=23π, and the x-axis be A. Then, A+A2 is equal to ____.
Held on 23 Jan 2026 · Verified 6 Jul 2026.
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