4x2+4x−3=(2x+3)(2x−1). For continuity at x=−3/2, numerator must vanish there:
a(9/4)−3a+3=0⇒a=4.
f(x)=(2x+3)(2x−1)(2x+1)(2x+3)=2x−12x+1 for x=−3/2.
f∘f(x)=f(2x−12x+1)=2x+36x+1.
2x+36x+1=57⇒30x+5=14x+21⇒x=1.
JEE Main 2026 — Mathematics Calculus
Let f(x)={4x2+4x−3ax2+2ax+3 b,x=−23,21,x=−23,21
be continuous at x=−23. If f∘f(x)=57, then x is equal to:
Held on 23 Jan 2026 · Verified 6 Jul 2026.
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