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Let f: R →(0, ∞) be a twice differentiable function such that f(3)=18, f^prime(3)=0 and f^prime prime(3)=4. Then lim _x → 1 (log _ e ( f(2+x) f(3) )^…

JEE Main 2026 — Mathematics Calculus

2026mcqhard

Let f:R→(0,∞)f: \mathbf{R} \rightarrow(0, \infty)f:R→(0,∞) be a twice differentiable function such that f(3)=18,f′(3)=0f(3)=18, f^{\prime}(3)=0f(3)=18,f′(3)=0 and f′′(3)=4f^{\prime \prime}(3)=4f′′(3)=4. Then lim⁡x→1(log⁡e(f(2+x)f(3))18(x−1)2)\displaystyle \lim _{x \rightarrow 1}\left(\log _{\mathrm{e}}\left(\frac{f(2+x)}{f(3)}\right)^{\frac{18}{(x-1)^{2}}}\right)x→1lim​(loge​(f(3)f(2+x)​)(x−1)218​) is equal to :

Official previous-year question

Held on 21 Jan 2026 · Verified 6 Jul 2026.

Options

  1. A

    1

  2. B

    18

  3. C

    2

  4. D

    9

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