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Let the function f(x)= (x^2+1 ) |x^2-a x+2 |+cos |x| be not differentiable at the two points x=α=2 and x=β. Then the distance of the point (α, β)…

JEE Main 2025 — Mathematics Calculus

2025mcqhard

Let the function f(x)=(x2+1)∣x2−ax+2∣+cos⁡∣x∣f(x)=\left(x^2+1\right)\left|x^2-a x+2\right|+\cos |x|f(x)=(x2+1)​x2−ax+2​+cos∣x∣ be not differentiable at the two points x=α=2x=\alpha=2x=α=2 and x=βx=\betax=β. Then the distance of the point (α,β)(\alpha, \beta)(α,β) from the line 12x+5y+10=012 x+5 y+10=012x+5y+10=0 is equal to :

Official previous-year question

Held on 29 Jan 2025 · Verified 6 Jul 2026.

Options

  1. A

    5

  2. B

    4

  3. C

    3

  4. D

    2

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