0≤9x≤y2&y≥3x−6
A= Required Area =[∫01(−3x)dx−∫01(3x−6)dx]A=−3(23x23)01−(23x2−6x)01A=−2[1−0][23−6]A=−2−23+6=25 Sq. unit ∴6A=6×25=15
JEE Main 2025 — Mathematics Calculus
Let the area of the bounded region {(x,y):0≤9x≤y2,y≥3x−6} be A. Then 6 A is equal to ________
Held on 8 Apr 2025 · Verified 6 Jul 2026.
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