f(x)=ex−11=e1−x
\begin{array}{c|c}\mathrm{f}(\mathrm{x})=2 & \mathrm{f}(\mathrm{x})=1 \\frac{1}{\mathrm{e}^{\mathrm{x}-1}}=2 & \mathrm{x}=1 \\mathrm{x}=1-\ln 2 &\end{array}
f(0)=e1=2.71
f(e3)=e1−e3∈(0,1)
I=∫01−ℓn22dx+∫1−ℓn211dx+∫1e30dx
=2(1−ℓn2−0)+1(1−1+ln2)+0
α−ln2=2−ln2
α=2
α3=8