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Let f: R → R be a twice differentiable function such that (sin x cos y)(f(2 x+2 y)-f(2 x-2 y))=(cos x sin y)(f(2 x+2 y)+f(2 x-2 y)), for all x, y ∈…

JEE Main 2025 — Mathematics Calculus

2025mcqhard

Let f:R→Rf: \mathbf{R} \rightarrow \mathbf{R}f:R→R be a twice differentiable function such that (sin⁡xcos⁡y)(f(2x+2y)−f(2x−2y))=(cos⁡x(\sin x \cos y)(f(2 x+2 y)-f(2 x-2 y))=(\cos x(sinxcosy)(f(2x+2y)−f(2x−2y))=(cosx sin⁡y)(f(2x+2y)+f(2x−2y))\sin \mathrm{y})(f(2 \mathrm{x}+2 \mathrm{y})+f(2 \mathrm{x}-2 \mathrm{y}))siny)(f(2x+2y)+f(2x−2y)), for all x,y∈R\mathrm{x}, \mathrm{y} \in \mathbf{R}x,y∈R.

If f′(0)=12f^{\prime}(0)=\frac{1}{2}f′(0)=21​, then the value of 24f′′(5π3)24 f^{\prime \prime}\left(\frac{5 \pi}{3}\right)24f′′(35π​) is:

Official previous-year question

Held on 2 Apr 2025 · Verified 6 Jul 2026.

Options

  1. A

    2

  2. B

    −3-3−3

  3. C

    3

  4. D

    −2-2−2

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