x2f′(x)−2xf(x)=3((x2)2x2f′(x)−2xf(x))=(x2)23⇒dxd(x2f(x))=x43 Integrating both sides $\begin{aligned}
& \frac{f(x)}{x^2}=-\frac{1}{x^3}+C \
& f(x)=-\frac{1}{x}+C x^2 \
& \text { put } x=1 \
& 4=-1+C \Rightarrow C=5 \
& f(x)=-\frac{1}{x}+5 x^2 \
& \text { Now } 2 \times f(2)=2 \times\left[-\frac{1}{2}+5 \times 2^2\right] \
& =39
\end{aligned}$
Let f:(0, ∞) → R be a function which is differentiable at all points of its domain and satisfies the condition x^2 f^prime(x)=2 x f(x)+3, with…
JEE Main 2025 — Mathematics Calculus
Let f:(0,∞)→R be a function which is differentiable at all points of its domain and satisfies the condition x2f′(x)=2xf(x)+3, with f(1)=4. Then 2f(2) is equal to :
Held on 24 Jan 2025 · Verified 6 Jul 2026.
Options
- A
39
- B
19
- C
29
- D
23
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