Diff. w.r.t. x
$\begin{aligned}
& g(x)=1-x g(x) \
& g(x)=\frac{1}{1+x} \
& \text { so } \frac{d y}{d x}-y \tan x=2 \sec x \
& I F=e^{-\int \tan d x}=e^{\log \cos x}=\cos x
\end{aligned}$
solution of D.E.
$\begin{aligned}
& y \cos x=\int 2 d x+c \
& y \cos x=2 x+c \
& y(0)=0
\end{aligned}$
c=0
y=cosx2xy=2xsecxy(3π)=2⋅3π⋅2=34π