dxdy=7+e2x2(3+y)⋅e2xdxdy−7+e2x2ye2x=7+e2x6⋅e2x I.F. =e−∫7+e2x2e2xdx⇒e−ln(7+e2x)=7+e2x1y⋅7+e2x1=∫(7+e2x)26e2xdx7+e2xy=7+e2x+C−3∴y(0)=5⇒85=8−3+C⇒C=1∴y=−3+7+e2xy=e2x+4∴k=8
JEE Main 2025 — Mathematics Calculus
Let a curve y=f(x) pass through the points (0,5) and (loge2,k). If the curve satisfies the differential equation 2(3+y)e2xdx−(7+e2x)dy=0, then k is equal to
Held on 23 Jan 2025 · Verified 6 Jul 2026.
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