Put x=1+hh→0limh3h(6+λcosh)−μsinh=−1h→0limh3h(6+λ(1−2!h2))−μ(h−3!h3)=−16+λ−μ=0 and −2λ+6μ=−1λ+μ=18
If lim _x → 1^+ (x-1)(6+λ cos (x-1))+μ sin (1-x) (x-1)^3=-1, where λ, μ ∈ mathbbR, then λ+μ is equal to
JEE Main 2025 — Mathematics Calculus
If x→1+lim(x−1)3(x−1)(6+λcos(x−1))+μsin(1−x)=−1, where λ,μ∈R, then λ+μ is equal to
Held on 4 Apr 2025 · Verified 6 Jul 2026.
Options
- A
18
- B
20
- C
19
- D
17
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