If the area of the larger portion bounded between the curves x^2+y^2=25 and y=|x-1| is 1 4(b π+c), b, c ∈ N, then b+c is equal to

$$\begin{aligned} & \mathrm{x}^2+\mathrm{y}^2=5 \\ & \mathrm{x}^2+(\mathrm{x}-1)^2=25 \Rightarrow \mathrm{x}=4 \\ & \mathrm{x}^2+(-\mathrm{x}+1)^2=5 \Rightarrow \mathrm{x}=-3 \\ & \mathrm{~A}=25 \pi-\int_{-3}^4 \sqrt{25-\mathrm{x}^2} \mathrm{dx}+\frac{1}{2} \times 4 \times 4+\frac{1}{2} \times 3 \times 3 \\ & \mathrm{~A}=25 \pi+\frac{25}{2}-\left[\frac{\mathrm{x}}{2} \sqrt{25-\mathrm{x}^2}+\frac{25}{2} \sin ^{-1} \frac{\mathrm{x}}{5}\right]_{-3}^4 \\ & \mathrm{~A}=25 \pi+\frac{25}{2}-\left[6+\frac{25}{2} \sin ^{-1} \frac{4}{5}+6+\frac{25}{2} \sin ^{-1} \frac{3}{5}\right] \\ & \mathrm{A}=25 \pi+\frac{1}{2}-\frac{25}{2} \cdot \frac{\pi}{2} \\ & \mathrm{~A}=\frac{75 \pi}{4}+\frac{1}{2} \\ & \mathrm{~A}=\frac{1}{4}(75 \pi+2) \\ & \mathrm{b}=75, \mathrm{c}=2 \\ & \mathrm{~b}+\mathrm{c}=75+2=77\end{aligned}$$​x2+y2=5x2+(x−1)2=25⇒x=4x2+(−x+1)2=5⇒x=−3 A=25π−∫−34​25−x2​dx+21​×4×4+21​×3×3 A=25π+225​−[2x​25−x2​+225​sin−15x​]−34​ A=25π+225​−[6+225​sin−154​+6+225​sin−153​]A=25π+21​−225​⋅2π​ A=475π​+21​ A=41​(75π+2)b=75,c=2 b+c=75+2=77​