x2+y2=5x2+(x−1)2=25⇒x=4x2+(−x+1)2=5⇒x=−3 A=25π−∫−3425−x2dx+21×4×4+21×3×3 A=25π+225−[2x25−x2+225sin−15x]−34 A=25π+225−[6+225sin−154+6+225sin−153]A=25π+21−225⋅2π A=475π+21 A=41(75π+2)b=75,c=2 b+c=75+2=77
If the area of the larger portion bounded between the curves x2+y2=25 and y=∣x−1∣ is 41(bπ+c),b,c∈N, then b+c is equal to
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