(2y−5)dxdy=−3(2y−5)dy=−3dx2⋅2y2−5y=−3x+λ ∵ Curve passes through (0,1) ⇒λ=−4 ∵ Curve will be (y−25)2=−3(x−43) ∴ Vertex of parabola will be (43,25) ∵2x+3y=9
JEE Main 2024 — Mathematics Calculus
The solution curve, of the differential equation 2y dxdy+3=5 dxdy, passing through the point (0,1) is a conic, whose vertex lies on the line:
Held on 9 Apr 2024 · Verified 6 Jul 2026.
2x+3y=9
2x+3y=−9
2x+3y=−6
2x+3y=6
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