Given: f(x)=2x+3(x)32
⇒f′(x)=2+2x3−1
⇒f′(x)=2(1+x311)
⇒f′(x)=2(x31x31+1)

The function changes from positive to negative at x=1 and from negative to positive at x=0
So, the point of local maxima (M) is at x=−1 and the point of local minima (m) at x=0