Given,
(y−2)2=x−1 and x−2y+4=0
Now, plotting the graph of the above equation, we get,

Now, from above diagram we get,
Required area =∫03xdy− Area of ΔABC.
=∫03((y−2)2+1)dy−21×1×2
=∫03(y2−4y+5)dy−1
=[3y3−2y2+5y]03−1
=9−18+15−1=5
JEE Main 2024 — Mathematics Calculus
The area of the region enclosed by the parabola (y−2)2=x−1, the line x−2y+4=0 and the positive coordinate axes is __________.
Held on 30 Jan 2024 · Verified 6 Jul 2026.
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