f′(x)=3x2sin(x1)−xcos(x1)f′′(x)=6xsin(x1)−3cos(x1)−cos(x1)−xsin(x1)f′′(π2)=π12−2π=2π24−π2
JEE Main 2024 — Mathematics Calculus
If f(x)={x3sin(x1),x=00,x=0 then
Held on 6 Apr 2024 · Verified 6 Jul 2026.
f′′(π2)=2π24−π2
f′′(π2)=2π12−π2
f′′(0)=1
f′′(0)=0
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