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If the function f(x)=2 x^3-9 x^2+12 a^2 x+1, a>0 has a local maximum at x=α and a local minimum at x=α^2, then α and α^2 are the roots of the…

JEE Main 2024 — Mathematics Calculus

2024mcqeasy

If the function f(x)=2x3−9x2+12a2x+1,a>0f(x)=2 x^3-9 x^2+12 \mathrm{a}^2 x+1, \mathrm{a}>0f(x)=2x3−9x2+12a2x+1,a>0 has a local maximum at x=αx=\alphax=α and a local minimum at x=α2x=\alpha^2x=α2, then α\alphaα and α2\alpha^2α2 are the roots of the equation :

Official previous-year question

Held on 8 Apr 2024 · Verified 6 Jul 2026.

Options

  1. A

    x2−6x+8=0x^2-6 x+8=0x2−6x+8=0

  2. B

    x2+6x+8=0x^2+6 x+8=0x2+6x+8=0

  3. C

    8x2+6x−1=08 x^2+6 x-1=08x2+6x−1=0

  4. D

    8x2−6x+1=08 x^2-6 x+1=08x2−6x+1=0

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