α=x→0+limextanx−x(etanx−x−1)=1β=x→0lim(1+sinx)21cotx=e1/2x2−(1+e)+e=0ax2+bx−e=0 On comparing a=−1,b=e+112ln(a+b)=12×21=6
JEE Main 2024 — Mathematics Calculus
If α=x→0+lim(tanx−xetanx−ex) and β=x→0lim(1+sinx)21cotx are the roots of the quadratic equation ax2+bx−e=0, then 12loge(a+b) is equal to__________
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