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Let f(x)=[x^2-x]+|-x+[x]|, where x∈ mathbbR and [t] denotes the greatest integer less than or equal to t. Then, f is

JEE Main 2023 — Mathematics Calculus

2023mcqeasy

Let f(x)=[x2−x]+∣−x+[x]∣f(x)=[{x}^{2}-x]+|-x+[x]|f(x)=[x2−x]+∣−x+[x]∣, where x∈Rx\in \mathbb{R}x∈R and [t][t][t] denotes the greatest integer less than or equal to ttt. Then, fff is

Official previous-year question

Held on 11 Apr 2023 · Verified 6 Jul 2026.

Options

  1. A

    continuous at x=0x=0x=0, but not continuous at x=1x=1x=1

  2. B

    continuous at x=1x=1x=1, but not continuous at x=0x=0x=0

  3. C

    continuous at x=0x=0x=0 and x=1x=1x=1

  4. D

    not continuous at x=0x=0x=0 and x=1x=1x=1

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