Let, the parabola be y=ax2+bx+c,
Now given parabola is passing through (-1,0),(0,1)&(1,0)
Now putting the value in the above equation of parabola we get,
a−b+c=0......(1), c=1....(2) and a+b+c=0....(3)
Now solving above three equations we get,
Parabola as y=1−x2
Now area of region between y=1−x2 and (x+1)2+(y−1)2≤1 is given by,

Now from above diagram, required area will be,
A=∫−10(−x2+1−(x+1)2)dx
⇒A=4π−31
Hence, 12(π−4A)=16