Let T and C respectively, be the transverse and conjugate axes of the hyperbola 16x2−y2+64x+4y+44=0. Then the area of the region above the parabola x2=y+4, below the transverse axis T and on the right of the conjugate axis C is:
Held on 25 Jan 2023 · Verified 6 Jul 2026.
46+344
46+328
46−344
46−328
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