We have been given thatdxdy=y+7⇒y+7dy=dx
⇒ln∣y+7∣=x+c
⇒∣y+7∣=k.ex
⇒y=k⋅ex−7
⇒y1(0)=0⇒k=7⇒y1(x)=7(ex−1)
⇒y2(0)=1⇒1=k−7⇒8=k
⇒y2(x)=8ex−7
⇒y1(x)=y2(x)⇒8ex−7=7ex−7
Hence, No point of intersection.
This is the required option.
Let y=y1(x) and y=y2(x) be the solution curves the differential equation dxdy=y+7 with initial conditions y1(0)=0 and y2(0)=1 respectively. Then the curves y=y1(x) and y=y2(x) intersect at
Held on 13 Apr 2023 · Verified 6 Jul 2026.
no point
two points
one point
infinite number of points
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