Given:
2{y}^{2}=3x,x+y=3(\mathrm{slope}\mathrm{is}-1)&{(x-3)}^{2}+{y}^{2}=2
Now plotting the diagram of the above function we have,

So, required area is
A=∫023(3−y−32y2)dy−360∘π(2)2×45∘
⇒A=[3y−2y2]023−32[3y3]023−4π
⇒A=821−4π
So,
A=41(221−π)
⇒π+4A=221
⇒4(π+4A)=42