Plotting region for ∣x−1∣≤y≤5−x2, we get,

The intersection points of the curves x2+y2=5 and y=∣x−1∣ will be (-1,2)&(2,1)
Here chord AB subtends a right angle at the centre of the circle.
So, required area = area of ΔABC+ area of segment of circle on chord AB
=21AC⋅BC+ [area of quarter circle − area of ΔAOB]
=21×2×22+(360∘90∘×π(5)2−21×(5)2)
=45π−21