The graph of y={x}^{2}&y=\mathrm{min}{x+2,4-3x} will be

From the graph,
required area A=∫−121(x+2−x2)dx+∫211(4−3x−x2)dx
=(2x2+2x−3x3)−121+(4x−32x2−3x3)211=617
JEE Main 2022 — Mathematics Calculus
The area of the region given by A=(x,y):x2≤y≤minx+2,4−3x is
Held on 25 Jul 2022 · Verified 6 Jul 2026.
831
617
619
827
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