f(x)= max ∣x+1∣,∣x+2∣,∣x+3∣,∣x+4∣,∣x+5∣
∫−60f(x)dx=∫−6−3∣x+1∣dx+∫−30∣x+5∣dx
=−∫−6−3(x+1)dx+∫−30(x+5)dx
=−[2x2+x]−6−3+[2x2+5x]−30
=−[(29−3)−(18−6)]+[0−(29−15)]
=−[23−12⌉+221=221+221=21
JEE Main 2022 — Mathematics Calculus
Let f(x)=max∣x+1∣,∣x+2∣,…,∣x+5∣. Then ∫−60f(x)dx is equal to ______.
Held on 26 Jun 2022 · Verified 6 Jul 2026.
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