
Intersection point of {y}^{2}=x&y=2|x| in the first quadrant will be (41,21)
Also, intersection point of y={x}^{3}&{y}^{2}=x in first quadrant will be (1,1)
Area of the region S=∫01(x−x3)dx =[32x23−4x4]10 =125
Area of region R1=∫041(x−2x)dx =[32x23−x2]041=481
∴R2=S−R1=4819
So, R1R2=19