Since xβ7limβ[xβ3a]18β[1βx]β exists (aβI)
β΄L.H.L=R.H.L
βhβ0limβ[7βhβ3a]18β(β6)β=hβ0limβ[7+hβ3a]18β(β7)β
βhβ0limβ(7β3a)+[βh]24β=hβ0limβ(7β3a)+[h]25β
β6β3a24β=7β3a25β βa=β6
Let a be an integer such that xβ7limβ[xβ3a]18β[1βx]β exists, where [t] is greatest integer β€t. Then a is equal to
Held on 27 Jun 2022 Β· Verified 6 Jul 2026.
β2
6
β6
β7
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