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Let P and Q be any points on the curves (x-1)^2+(y+1)^2=1 and y=x^2, respectively. The distance between P and Q is minimum for some value of the…

JEE Main 2022 — Mathematics Calculus

2022mcqmedium

Let PPP and QQQ be any points on the curves (x−1)2+(y+1)2=1{(x-1)}^{2}+{(y+1)}^{2}=1(x−1)2+(y+1)2=1 and y=x2y={x}^{2}y=x2, respectively. The distance between PPP and QQQ is minimum for some value of the abscissa of PPP in the interval

Official previous-year question

Held on 26 Jul 2022 · Verified 6 Jul 2026.

Options

  1. A

    (0,14)(0,\frac{1}{4})(0,41​)

  2. B

    (12,34)(\frac{1}{2},\frac{3}{4})(21​,43​)

  3. C

    (14,12)(\frac{1}{4},\frac{1}{2})(41​,21​)

  4. D

    (34,1)(\frac{3}{4},1)(43​,1)

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