Given dxdy=(1+y)(x−1)
⇒(y+1)dy=(x−1)dx
Integrate both the sides we get,
ln(y+1)=2x2−x+c
Given y(0)=0⇒c=0
∴y=e(2x2−x)−1
JEE Main 2021 — Mathematics Calculus
Which of the following is true for y(x) that satisfies the differential equation
dxdy=xy−1+x−y;y(0)=0
Held on 17 Mar 2021 · Verified 6 Jul 2026.
y(1)=e−21−1
y(1)=e21−e−21
y(1)=1
y(1)=e21−1
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