I=∫−11x2e[x3]dx=∫−10x2e[x3]dx+∫01x2e[x3]dx
=∫−10x2e−1dx+∫01x2e0dx
=e1×3x3∣0−1+3x3∣01
=e1×(0−(3−1))+31
=3e1+31=3e1+e
JEE Main 2021 — Mathematics Calculus
The value of ∫−11x2e[x3]dx, where [t] denotes the greatest integer ≤t, is :
Held on 25 Feb 2021 · Verified 6 Jul 2026.
3e+1
3ee−1
3e1
3ee+1
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