y−x=2,x2=y
Now, x2=2+x
⇒x2−x−2=0
⇒(x+1)(x−2)=0⇒x=−1,2
Required area=∫−12(2+x−x2)dx
=∣2x+2x2−3x3∣−12
=(4+2−38)−(−2+21+31)
=6−3+2−21=29 square units
JEE Main 2021 — Mathematics Calculus
The area of the region bounded by y−x=2 and x2=y is equal to :-
Held on 27 Jul 2021 · Verified 6 Jul 2026.
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