The given curves are x2+2y−1=0,y2+4x−4=0 and y2−4x−4=0.
Drawing their graphs, we get

The required area is shown by the shaded part and since the curves y2+4x−4=0 and y2−4x−4=0 are symmetric about the y-axis, hence they have the same area.
Hence, the required area=2[∫02(44−y2)dy−∫01(21−x2)dx]
=2[∫0241(4−y2)dy−∫0121(1−x2)dx]
=2[41(4y−3y3)02−21(x−3x3)01]
=2[41(8−38−0)−21(1−31−0)]
=2[34−31]=2sq.units .