A=∫0π/2((cosx+sinx)−∣cosx−sinx∣)dx
A=∫0π/4((cosx+sinx)−(cosx−sinx))dx+∫π/4π/2((cosx+sinx)−(sinx−cosx))dx
A=2∫0π/4sinxdx+2∫π/4π/2cosxdx
=2(−21+1)+2(1−21)=4−22=22(2−1)
JEE Main 2021 — Mathematics Calculus
The area, enclosed by the curves y=sinx+cosx and y=∣cosx−sinx∣ and the lines x=0,x=2π, is :
Held on 1 Sept 2021 · Verified 6 Jul 2026.
22(2+1)
22(2−1)
4(2−1)
2(2+1)
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