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Let g(x)=∫ _0^xf(t)dt, where f is continuous function in [0,3] such that 1 3≤ f(t)≤ 1 for all t∈ [0,1] and 0≤ f(t)≤ 1 2 for all t∈ (1,3]. The largest…

JEE Main 2021 — Mathematics Calculus

2021mcqeasy

Let g(x)=∫0xf(t)dt\displaystyle g(x)={\int }_{0}^{x}f(t)dtg(x)=∫0x​f(t)dt, where fff is continuous function in [0,3][0,3][0,3] such that 13≤f(t)≤1\frac{1}{3}\leq f(t)\leq 131​≤f(t)≤1 for all t∈[0,1]t\in [0,1]t∈[0,1] and 0≤f(t)≤120\leq f(t)\leq \frac{1}{2}0≤f(t)≤21​ for all t∈(1,3]t\in (1,3]t∈(1,3].

The largest possible interval in which g(3)g(3)g(3) lies is :

Official previous-year question

Held on 18 Mar 2021 · Verified 6 Jul 2026.

Options

  1. A

    [−1,−12][-1,-\frac{1}{2}][−1,−21​]

  2. B

    [−32,−1][-\frac{3}{2},-1][−23​,−1]

  3. C

    [13,2][\frac{1}{3},2][31​,2]

  4. D

    [1,3][1,3][1,3]

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