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If α ,β are the distinct roots of x^2+bx+c=0, then undersetx→ β lim e^2(x^2+bx+c)-1-2(x^2+bx+c) (x-β )^2 is equal to

JEE Main 2021 — Mathematics Calculus

2021mcqmedium

If α,β\alpha ,\betaα,β are the distinct roots of x2+bx+c=0,{x}^{2}+bx+c=0,x2+bx+c=0, then limx→βe2(x2+bx+c)−1−2(x2+bx+c)(x−β)2\underset{x\rightarrow \beta }{\mathrm{lim}}\frac{{e}^{2({x}^{2}+bx+c)}-1-2({x}^{2}+bx+c)}{(x-\beta {)}^{2}}x→βlim​(x−β)2e2(x2+bx+c)−1−2(x2+bx+c)​ is equal to

Official previous-year question

Held on 27 Aug 2021 · Verified 6 Jul 2026.

Options

  1. A

    2(b2+4c)2({b}^{2}+4c)2(b2+4c)

  2. B

    b2−4c{b}^{2}-4cb2−4c

  3. C

    2(b2−4c)2({b}^{2}-4c)2(b2−4c)

  4. D

    b2+4c{b}^{2}+4cb2+4c

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