dxdy−ln(y+3x)y+3x+3=0
dxdy+3=ln(y+3x)y+3x
dxd(y+3x)=ln(y+3x)y+3x
∫(y+3x)ln(y+3x)d(y+3x)=∫dx
Let ln(y+3x)=t
(y+3x)1d(y+3x)=dt
∫tdt=∫dx
2t2=x+c
2(ln(y+3x))2=x+c
JEE Main 2020 — Mathematics Calculus
The solution of the differential equation dxdy−loge(y+3x)y+3x+3=0 is
(where C is a constant of integration)
Held on 4 Sept 2020 · Verified 6 Jul 2026.
x−21(loge(y+3x))2=C
x−loge(y+3x)=C
y+3x−21(logex)2=C
x−2loge(y+3x)=C
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