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Let f(x)=x cos^-1⁡(- sin⁡|x|),x∈ [- π 2, π 2], then which of the following is true?

JEE Main 2020 — Mathematics Calculus

2020mcqhard

Let f(x)=xcos−1⁡(−sin⁡∣x∣),x∈[−π2,π2],f(x)=x{\mathrm{cos}}^{-1}⁡(-\mathrm{sin}⁡|x|),x\in [-\frac{\pi }{2},\frac{\pi }{2}],f(x)=xcos−1⁡(−sin⁡∣x∣),x∈[−2π​,2π​], then which of the following is true?

Official previous-year question

Held on 8 Jan 2020 · Verified 6 Jul 2026.

Options

  1. A

    f′f'f′ is increasing in (−π2,0)(-\frac{\pi }{2},0)(−2π​,0) and decreasing in (0,π2)(0,\frac{\pi }{2})(0,2π​)

  2. B

    f′(0)=−π2{f}^{'}(0)=-\frac{\pi }{2}f′(0)=−2π​

  3. C

    fff is not differentiable at x=0x=0x=0

  4. D

    f′f'f′ is decreasing in (−π2,0)(-\frac{\pi }{2},0)(−2π​,0) and increasing in (0,π2)(0,\frac{\pi }{2})(0,2π​)

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