f(g(x))=x
⇒f′(g(x)).g′(x)=1
Put x=a
⇒f′(g(a))g′(a)=1
⇒f′(b)×5=1
⇒f′(b)=51
JEE Main 2020 — Mathematics Calculus
Let f and g be differentiable functions on R such that fog is the identity function. If for some a,b∈R,g′(a)=5 and g(a)=b, then f′(b) is equal to:
Held on 9 Jan 2020 · Verified 6 Jul 2026.
51
1
5
52
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