x→1limx−1x+x2+x3+….+xn−n=820(00)form
Applying L'Hospital rule
x→1lim11+2x+3x2+…..+nxn−1=820
⇒1+2+3+……+n=820
⇒2n(n+1)=820
⇒n2+n=1640
⇒n2+n−1640=0
⇒n=40,−41
Since n is natural number ⇒n=40.
JEE Main 2020 — Mathematics Calculus
If x→1limx−1x+x2+x3+...+xn−n=820,(n∈N) then the value of n is equal to....
Held on 2 Sept 2020 · Verified 6 Jul 2026.
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