Clearly p′(x)=λ(x−1)(x−2) where λ>0
Integrating both sides
p(x)=λ[3x3−23x2+2x]+C
Given
p(1)=8⇒λ(31−23+2)+C=8⇒65λ+C=8...(1)
p(2)=4⇒λ(38−6+4)+C=4⇒32λ+C=4...(2)
By (1) and (2) ⇒C=−12
⇒p(0)=−12
JEE Main 2020 — Mathematics Calculus
If p(x) be a polynomial of degree three that has a local maximum value 8 at x=1 and a local minimum value 4 at x=2 then p(0) is equal to
Held on 2 Sept 2020 · Verified 6 Jul 2026.
6
−12
24
12
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