Area = ∫₀² x² dx = [x³/3]₀² = 8/3 - 0 = 8/3 sq units
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JEE Main 2020 — Mathematics Calculus
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mcq
2020
Official previous-year question
Verified 30 May 2026.
Question
The area bounded by y = x², x-axis, and x = 2 is:
Options
- A4/3
- B8/3
- C4
- D8
Solution
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