
The equation of parabola x2=y−1 The equation of tangent at (2,5) to parabola is y−5=(dxdy)(2,5)(x−2) y−5=4(x−2) 4x−y=3 Then, the required area =∫02{(x2+1)−(4x−3)}dx− Area of ΔAOD =∫02(x2−4x+4)dx−21×43×3 =[3(x−2)3]02−89=2437
JEE Main 2019 — Mathematics Calculus
The area (in sq. units) in the first quadrant bounded by the parabola, y=x2+1, the tangent to it at the point (2,5) and the coordinate axes is :
Held on 11 Jan 2019 · Verified 6 Jul 2026.
38
2437
24187
314
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