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If 2y=( cot^-1( √3 cosx+ sinx cosx-√3 sinx))^2forall x∈ (0, π 2), then dy dxis equal to

JEE Main 2019 — Mathematics Calculus

2019mcqhard

If 2y=(cot−1(3cosx+sinxcosx−3sinx))2∀x∈(0,π2)2y={({\mathrm{cot}}^{-1}(\frac{\sqrt{3}\mathrm{cos}x+\mathrm{sin}x}{\mathrm{cos}x-\sqrt{3}\mathrm{sin}x}))}^{2}\forall x\in (0,\frac{\pi }{2})2y=(cot−1(cosx−3​sinx3​cosx+sinx​))2∀x∈(0,2π​), then dydx\frac{dy}{dx}dxdy​is equal to

Official previous-year question

Held on 8 Apr 2019 · Verified 6 Jul 2026.

Options

  1. A

    π6−x\frac{\pi }{6}-x6π​−x

  2. B

    2x−π32x-\frac{\pi }{3}2x−3π​

  3. C

    x−π6x-\frac{\pi }{6}x−6π​

  4. D

    None of these

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