The given equations are y2=4λx and y=λx
Using above equations, we can write
(λx)2=4λx⇒λ2x2−4λx=0
⇒λx(λx−4)=0
\Rightarrow x=0&x=\frac{4}{\lambda }

Area =91=∫0λ4(4λx−λx)dx
⇒(234λx23−2λx2)0λ4=91
⇒λ=24
Hence, the required value is 24.
JEE Main 2019 — Mathematics Calculus
If the area (in sq. units) bounded by the parabola y2=4λx and the line y=λx,λ>0, is 91, then λ is equal to
Held on 12 Apr 2019 · Verified 6 Jul 2026.
43
26
48
24
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