x→0lim2−1+cosxsin2x
On Rationalisation, we get,
=x→0lim2−1+cosxsin2x×2+1+cosx2+1+cosx
=x→0lim1−cosx(2sin2xcos2x)2×(2+1+cosx)
=x→0lim2sin22x4sin22xcos22x×(2+1+cosx)
=x→0lim2cos22x(2+1+cosx)=2×22
=42.
JEE Main 2019 — Mathematics Calculus
x→0lim2−1+cosxsin2x equals
Held on 8 Apr 2019 · Verified 6 Jul 2026.
42
22
2
4
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