∵7−6x−x2=16−(x+3)2 and dxd(7−6x−x2)=−2x−6 So, ∫7−6x−x22x+5dx=∫7−6x−x22x+6dx −∫16−(x+3)21dx =−27−6x−x2−sin−1(4x+3)+C Therefore, A=−2,&B=−1.
JEE Main 2018 — Mathematics Calculus
∫7−6x−x22x+5dx=A7−6x−x2+Bsin−1(4x+3)+C (where C is a constant of integration), then the ordered pair (A,B) is equal to
Held on 15 Apr 2018 · Verified 6 Jul 2026.
(−2,−1)
(2,−1)
(−2,1)
(2,1)
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