Given, x=2cosec−1t=22cosec−1t and y=2sec−1t=22sec−1t, then we have
x⋅y=22sec−1t+cosec−1t
And, we know that sec−1x+cosec−1x=2π,
⇒xy=24π
On differentiating, both sides with respect to x, and applying product rule, we get
xdxdy+y=0
⇒dxdy=−xy.
JEE Main 2018 — Mathematics Calculus
If x=2cosec−1t and y=2sec−1t,(∣t∣≥1), then dxdy is equal to
Held on 16 Apr 2018 · Verified 6 Jul 2026.
xy
−xy
−yx
yx
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