
Required Area
=∫01(1+x)dx+∫12(3−x)dx−∫024x2dx
=[x+32x23]01+[3x−2x2]12−[12x3]02
=(1+32)+(4−25)−32
=25sq.units
JEE Main 2017 — Mathematics Calculus
The area (in sq. units) of the region (x,y):x≥0,x+y≤3,x2≤4yandy≤1+x is
Held on 2 Apr 2017 · Verified 6 Jul 2026.
1259sq.units
23sq.units
37sq.units
25sq.units
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