f(2−x)=f(2+x) and f(4−x)=f(4+x)
Then curve is symmetric about x=2 and x=4
∴ The curve is periodic with period 4
Given ∫02f(x)dx=5
∫04f(x)dx=2∫02f(x)dx=10
∫1050f(x)dx=∫2(4)+212(4)+2f(x)dx
=(12−2)∫04f(x)dx
=10×10=100
JEE Main 2015 — Mathematics Calculus
Let f:R→R be a function such that f(2−x)=f(2+x) and f(4−x)=f(4+x), for all x∈R and ∫02f(x)dx=5. Then the value of ∫1050f(x)dx is
Held on 11 Apr 2015 · Verified 6 Jul 2026.
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